Mr. Ramirez can use many different group sizes, but the largest group size possible is 8. This results in 16/8=2 sixth-grade groups and 24/8=3 seventh-grade groups.
Answer:
806.12 m
Step-by-step explanation:
<u>Step 1: Write the data</u>
<em>Side (s) = 12</em>
<em>Altitude (h) = 6</em>
<u>Step 2: Write the formula for surface area of right hexagonal pyramid</u>
<em>Area = 3√3/2*s² + 3*s*√(h²+3s²/4)</em>
<u>Step 3: Substitute values of 's' and 'h'</u>
<em>Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]</em>
Area = 806.12 m
Therefore, the total surface area of the pyramid is 806.12 m.
!!
Answer: The figure drawn by Alan is a rhombus.
Step-by-step explanation:
Given: Allan drew a polygon with 4 sides and 4 angles with two properties:-
- All four sides are equal.
- None of the angles are right angles.
We know that only a rhombus is a flat shape with 4 equal straight sides and 4 angles .All sides have equal length. Its angles need not to be right angle.
Therefore, the figure drawn by Alan is a rhombus.
Answer:
<em>a) </em>
<em />
<em>b) The coordinates of P are</em>
<em />
Step-by-step explanation:
<u>Translation</u>
The dashed line shows the graph of the function
This function has a maximum value of 1, a minimum value of -1, and a center value of 0.
a)
Graph G shows the same function but translated by 2 units up, thus the equation of G is:
b) The coordinates of P correspond to the value of
The value of G is
Since
The coordinates of P are
Draw a line through R parallel to the segment PQ
First choice.
