Answer:
F is the midpoint of AA' because Line E G bisects AA'
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
When reflecting a figure, the image is congruent to the pre-image.
A reflection maps every point of the pre-image to an image across a fixed line. The fixed line is called the line of reflection.
The distance of each point of the pre-image from the line of reflection will be the same as the distance of each point of image from the line.
In this problem the line of reflection is E G
The distance A F is equal to the distance A'F
Point F is the midpoint segment A A'
so
Line segment E G bisects segment A A'
therefore
F is the midpoint of A A' because Line E G bisects A A'
