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ExtremeBDS [4]
3 years ago
5

FH and IK are parallel lines.

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0

Ans

the bottom one

Step-by-step explanation:

yes, hope this helps

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What is 20x20+2-27+100
kupik [55]

Answer:

475 is the answer. hope that helped

5 0
3 years ago
78*2345=? multiply please
PSYCHO15rus [73]
The answer to this question is:

182910
3 0
3 years ago
Read 2 more answers
Make a ten or hundred to add mentally 198+132
Veseljchak [2.6K]
2000. Because if you add the 2  it will make 1200, 2+8 is 10 so you carry the 1, and 3+9 is 12 then you add the 1 you got from 10 and you have 13. then you add 1+1 and get 2 and add the 1 you got from 13 so there you have it.
6 0
3 years ago
A master student is planning to take a qualifying exam in the coming summer. She has three chances. The first one is in June. If
Soloha48 [4]

Answer:

Step-by-step explanation:

Given

P_1=Probability of clearing exam in 1 st attempt=0.5

P_2=Probability of clearing exam in 2 nd attempt=0.7

P_3=Probability of clearing exam in 3 rd attempt=0.8

Probability that she passes the exam=P(1 st\ attempt)+P(1\ fail)\cdot P(2\ pass)+P(1\ fail)\cdot P(2\ fail)\cdot P(3 rd pass)

P=0.5+0.5\times 0.7+0.5\times 0.3\times 0.8=0.97

(b)P(Pass qualification on 2nd try|passes qualification)

P(Pass qualification on 2nd try|passes qualification)=\frac{P(fail\ on\ 1 )\cdot P(pass\ in\ 2nd)}{P(passes)}

P(Pass qualification on 2nd try|passes qualification)=\frac{0.5\times 0.7}{0.97}=0.3608

5 0
3 years ago
If a polynomial function f(x) has roots 1+square root of 2 and-3, what must be a factor of f(x)?
nevsk [136]
To find the factor a a polynomial from its roots, we are going to seat each one of the roots equal tox, and then we are going to factor backwards.

We know for our problem that one of the roots of our polynomial is -3, so lets set -3 equal tox and factor backwards:
x=-3
x+3=0
(x+3) is a factor of our polynomial.

We also know that another root of our polynomial is 1+ \sqrt{2}, so lets set 1+ \sqrt{2} equal to x and factor backwards:
x=1+ \sqrt{2}
x-1= \sqrt{2}
x-1- \sqrt{2}=0
(x-(1+ \sqrt{2})=0
((x-(1+ \sqrt{2} )) is a factor of our polynomial.

We can conclude that there is no correct answer in your given choices.
8 0
4 years ago
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