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3 years ago

FH and IK are parallel lines.

Mathematics

1 answer:

SOVA2 [1]3 years ago

6 0

Ans

the bottom one

Step-by-step explanation:

yes, hope this helps

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BRAINLIEST ANSWER WINS! A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is sh

bekas [8.4K]

Answer:

D. x²/1953² + y²/ 1466² = 1

Step-by-step explanation:

==>Given:

Radius of spherical moon = 1000km

Distance of satellite from moon surface = 953km to 466km

==>Required:

Derived equation of ellipse

==>Solution:

The formula for driving an equation of ellipse is given as:

x²/a² + y²/b² = 1

Where,

a = length of the semi-major axis, while,

b = length of the semi-major axis

Since we are told that the satellite distance to the surface of the moon varies from 953km to 466km, values of a and b is calculated by summing each length to the radius of the moon as follows:

a = radius of moon + the larger distance of the satellite = 1000+953 = 1,953km

b = radius of moon + the smaller distance of the satellite = 1000+466 = 1,466km

Thus, the equation of the ellipse would be:

x²/1953² + y²/ 1466² = 1

8 0

3 years ago

Find the correct value of x

bearhunter [10]

Answer: x = 20

Step-by-step explanation:

Right angle = 90

90 - 47 = 43

43 - 3 = 40

40/2 = 20

3 0

3 years ago

I NEED HELP PLEASE. LOOK AT PICTURE

Bond [772]

Answer:

Part 1) $\frac{a^4}{4b^2}$

Part 2) $-\frac{v^9}{w^6}$

Step-by-step explanation:

we know that

When divide exponents (or powers) with the same base, subtract the exponents

Part 1) we have

$\frac{3a^{2}b^{-4}}{12a^{-2}b^{-2}}=(\frac{3}{12})(a^{2+2})(b^{-4+2} )=\frac{1}{4}a^{4}b^{-2}=\frac{a^4}{4b^2}$

Part 2) we have

$\frac{v^3w^{-3}}{-v^{-6} w^3} =-v^{3+6}w^{-3-3}=-v^9w^{-6}=-\frac{v^9}{w^6}$

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3 years ago

Segment Addition Postulate Task Cards

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Oppor it plenty no flow
Mafo any body

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3 years ago

I WILL GIVE BRAINLIST

docker41 [41]

I’m pretty sure it’s true

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3 years ago