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3 years ago

How do i find the power of a product?

Mathematics

1 answer:

Artyom0805 [142]3 years ago

4 0

If you mean something like 4^3 * 4^14 you have to obey two rules.

1. The base number must be the same for both numbers making up the product.

2. The powers must be added.

In this case 1 and 2 both can be obeyed.

4^3 * 4^14 = 4^(3 + 14) = 4^17

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does anyone understand this or can anyone explain what i need to do please ?? there’s no instructions

Contact [7]

Answer:

nah man... good luck tho

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2 years ago

A circle has a radius of 12cm. What is the area of that circle? Round to the nearest tenth. ( A = nr withe the 2 on top of the r

sergejj [24]

Area=Pi r squared Pi*12*12 452.39cubic cm To the nearest tenth =452.4cubic cm

3 0

3 years ago

12x + 3x = ___? Please explain

Paladinen [302]

Answer:15x

Step-by-step explanation:you add 12 + 3 which equals 15 and then you just carry the x over

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3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago

The equation 24x2+25x−47 ax−2 =−8x−3− 53 ax−2 is true for all values of x≠ 2 a , where a is a constant. What is the value of a?

Snowcat [4.5K]

The correct answer is B) -3

I am 100% positive

7 0

3 years ago

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