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2 years ago

I need help this is hard please help me

Mathematics

2 answers:

satela [25.4K]2 years ago

7 0

Answer:

$p(t)=25000e^{1.12t}$

Step-by-step explanation:

The expression exponential growth is applied to a magnitude such that its variation in time is proportional to its value, which implies that it grows faster and faster in time, according to the equation:

$f(x)=ab^{x}$

So, we can modeling an equation that describes the increasing of the population of Madison.

The town of Madison has a population of 25,000. The population is increasing by a factor of 1.12 each year.

$p(t)=p(0)e^{rt}$

Where p(t) is the population increase in a t years, p(0) is the initial population, r is the increasing factor, and t the amount of years elapsed.

So, we obtain:

$p(t)=25000e^{1.12t}$

Mademuasel [1]2 years ago

3 0

Answer:

P(t)=25000+1.12t

Step-by-step explanation:

Now can you help me?

A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function:

f(t) = −16t2 + 16t + 32

Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?

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What is the value of x in the triangle?

Ksivusya [100]

Answer:

X = 102

Step-by-step explanation:

41 + 37 + x = 180

78 + x = 180

X = 180 - 78 = 102

7 0

2 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$