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Nutka1998 [239]
4 years ago
11

Help me with 16 please

Mathematics
1 answer:
Ksivusya [100]4 years ago
5 0
357/4 is the answer I'm not sure
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ASAP ASAP ASAP ASAP MATH MATH MATH homework
Brut [27]

Answer:

$20

Step-by-step explanation:

Simple, if he sold 16 pretzels, and each one costs $1.25, then multiply the cost by how many:

16X1.25=20

So he got $20

I hope this helps!

5 0
3 years ago
Graph the equation: x = y^2 - 2
Lesechka [4]
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get 
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)

for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y 
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)

then plot the points on the graph
5 0
3 years ago
Jamar works at Jay's Jeweler. He earns $385 a week plus commission. Last week his sales totaled $1,680. If his commission is 25%
-BARSIC- [3]
$805

25% of $1,680 is $420 .
$420+$385= $805
4 0
3 years ago
Read 2 more answers
102/159 = x/4<br><br> Find X
-BARSIC- [3]
102/159 = x/4
34/53 = x/4
34(4) = x(53)
136 = 53x
136/53 = x
5 0
3 years ago
The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Volume = \pi r^2h

Where r is the radius and

h is the height of cylinder.

As per question statement:

r = 40 km (variable)

h = 2.5 (constant)

\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec

4 0
3 years ago
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