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zloy xaker [14]
3 years ago
13

In ΔPQR, the measure of ∠R=90°, the measure of ∠Q=38°, and RP = 72 feet. Find the length of PQ to the nearest tenth of a foot.

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0

Answer:

116.9FT

Step-by-step explanation:

lubasha [3.4K]3 years ago
7 0

Answer:74

Step-by-step explanation:

Since RP is 72, you would divide 72 by 2. The quotient you would get is 36. So then Q=38, you would add 36+38 and get 74.

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Answer:

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Step-by-step explanation:

First we calculate the slope as difference between coordinates

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m =  Δy/Δx      ⇒  m  =  (  y₂ - y₁ ) / ( x₂ - x₁ )  ⇒  m = (2 -6 ) / (3 -(-1))

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Now we have:

y - y₁  = m ( x - x₁ )    ⇒  y  -  6  = (-1) ( x - (-1))

y  -  6  =  -1 * ( x + 1 )   ⇒  y  -  6  =  - x - 1

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Q₁  ( -3 , 0 )  Q₂  ( 5  , 4 )

Again we calculate the slope

m  =  Δy / Δx    ⇒  m  =  ( 4 - 0 ) / ( 5 - (-3))    ⇒  m =  4 / 8   ⇒ m = 1/2

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And

y - y₁  = 1/2 ( x - x₁ )   ⇒  y  -  y₁  = 1/2 ( x - (-3))   ⇒   y  - 0 = 1/2 * x + 3/2

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