Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
finding the number of equal-sized parts into which a number can be split
Step-by-step explanation:
Let us split the number 80 into 10 equal parts.
80 = 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8
= 8 + 8 + 8 +...to 10 times
= 8(10)
or 
So, if N is any number and p is one of its equal part, then the number of parts into which N is split by p is
.
Hence, finding the number of equal-sized parts is best modeled with a division expression.
The simple interest would be $210. I hope that helps!
Answer:
6400
Step-by-step explanation:
its 6400 to the nearest hundred