Question

SOMEONE PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)]
πr^2 = π(4t)^2  =π4^2*t^2=  16πt^2 

Part B: A= 16π(4)^2 = 256π= 803.84 

here ya go c:

Answer 2

Answer:

Part A:

Setting up the problem: A[r(t)] =  π (4t)^2

= Multiplying: A[r(t)] = 3.14 x 16t^2  

= Solving/Answer:  A[r(t)] = 50.24t^2

Part B: Area after 4 min of spilling = t=4

= r (4)= 4x4 =16

= Setting up the problem: A(16) = 3.14 x 16^2

= Multiplying:  A(16)= 3.14 x 256

= Solving/Answer: A(16) = 803.84

= The spilled area of milk after 4 min is 803.84.