What is the product of x(5x + x^2)

Mathematics

1 answer:

amid [387]3 years ago

4 0

Answer:

The product is $x^3+5x^2$

Step-by-step explanation:

This is because we apply the distributive property of multiplication.

Thus from $x(5x+x^2)$

we get this:

$x*5x+x*x^2$

$x*5x$ is $5x^2$ and $x*x^2$ is $x^3$

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Step-by-step explanation:

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3 years ago

What is the value of this expression when a= - 3 and b=-2?<br> (3a^-2b^6/2a^-1b^5)^2

lisabon 2012 [21]

Answer:

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Hope This Helps!!!

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3 years ago

PLEASE HELP ME!!

Ludmilka [50]

Answer:

<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

$P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 = \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t} = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t} = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t} = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\$