how many 16 oz bottles would be needed to hold the same total amount of water as 56 bottles that each holds 20 oz?

2 answers:

7 0

So first find how many total oz there are in 56 bottles full of 20 oz by multiplying 56 and 20 together giving you 1120 oz. Now divide that by 16 to get your answer, 70 bottles.

AfilCa [17]2 years ago

7 0

To do this, you would find out how many oz 56 20 oz bottles holds. That's 1120. Then divide that by 16 to get 70.

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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%20%7B%7D%5E%7B2%7D%20%20-%205" id="TexFormula1" title="f(x) = x {}^{2} - 5

faust18 [17]

Answer:

The vertex is (0, -5) and the axis of symmetry is x = 0.

Step-by-step explanation:

In order to find the axis of symmetry, we look for the x value of the vertex. We can find this using the equation -b/2a, in which a is equal to the coefficient of the x^2 term and b is the coefficient of the x term.

x = -b/2a

x = 0/2(1)

x = 0/2

x = 0

So the axis of symmetry is 0 as is the x value of the vertex. Now we can find the y value by plugging in the x value into the equation.

f(x) = x^2 - 5

f(x) = 0^2 - 5

f(x) = 0 -5

f(x) = -5

This gives us a vertex of (0,-5)

7 0

2 years ago

Solve for x

Tems11 [23]

Answer:

---------

Step-by-step explanation:

x-3= -9

x= -9/ 3

x= -3

( -3x)-5 =16

-3x = 16+5

×= 21/-3

x = -7

8 0

2 years ago

And DVD cost $26.75 before sale tax sale tax is 7.5% what is the total of cost of DVDs

blondinia [14]

First let's convert 7.5% into a decimal by doing Beyoncé on it and move the decimal two places to the left.

$7.5\% = 0.075$

Now let's multiply the cost of the DVD by the converted percent,

$26.75 \times 0.075 = 2.00$
Now let's add the above number to the original price, remember, $2 is not exact.

$26.75 + 2.00 = 28.75$
~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

6 0

3 years ago

Help pls don't get it wrong I have an election tmr to see if I have good grades pls help

vfiekz [6]

<h3>SO, WHERE IS YOUR QUESTION?</h3>

BTW,,

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