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adell [148]
3 years ago
14

how many 16 oz bottles would be needed to hold the same total amount of water as 56 bottles that each holds 20 oz?

Mathematics
2 answers:
AnnZ [28]3 years ago
7 0
So first find how many total oz there are in 56 bottles full of 20 oz by multiplying 56 and 20 together giving you 1120 oz. Now divide that by 16 to get your answer, 70 bottles.
AfilCa [17]3 years ago
7 0
To do this, you would find out how many oz 56 20 oz bottles holds. That's 1120. Then divide that by 16 to get 70.
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gladu [14]
6!+7!+8!=(n)(6!)
calculate the individual values first:
6!=720
7!=5040
8!=40320

plug them into the equation:
720+5040+40320=n720
solve for n
5760+40320=n720
46080=n720
divide both sides by 720 to isolate n
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Answer:

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1 year ago
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weeeeeb [17]

To solve this function, all we need to do is substitute -4.3 in for wherever "x" appears and then simplify.

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Note: It may help to remember that, in a function such as this, f(x) can be thought of as the "y" value that corresponds to the given "x" value (in fact, when writing it out with words, f(x) is the same as "function of x"). And, if you are given a value for f(x), then the opposite is true. Just substitute in the value given for f(x) and solve for x.

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