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3 years ago

a math club has 40 members. The number of girls is 5 less the number of boy. what are the two equations solve

Mathematics

1 answer:

Gnom [1K]3 years ago

8 0

Well u could do 5 divided by 40 that will give u 8 or.....
U could do 40 divided by 5 and it will give u 8

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The two Marked angles are congruent yes or no will mark brainest

kompoz [17]

Answer:

true

Step-by-step explanation:

if the vertical lines are not parallel, then the corresponding angles are not congruent.

8x + 2 = 14x - 76

8x - 14x = -76 -2

-6x = -78

x = 13

8(13) + 2 = 14(13) - 76

106 = 106---- equal

the vertical lines is a bit confusing.... they looks like not a parallel lines

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3 years ago

The height of a cylindrical can is 4 7/16 inches and the radius is 3 inches. Which measurement is closest to the total surface a

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Step-by-step explanation:

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2 years ago

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poizon [28]

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Step-by-step explanation:

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3 years ago

Which ordered pair is a solution of the equation? −7x+3y=2

lana66690 [7]

Answer:

(-2/7, 2/3)

step-by-step explanation:
-7x + 3y = 2
x = 0
-7(0) + 3y = 2
3y = 2
/3 /3
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y = 0
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-7x = 2
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3 years ago

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The average discharge at the mouth of the Amazon River is 4,900,000 cubic feet per second. How much water is discharged from the

Misha Larkins [42]

Answer: Average discharge at the mouth of the Amazon River in 1 hour = $1.764\times 10^{10}$ cubic feet

Average discharge at the mouth of the Amazon River in 1 year= $3.66912\times10^{13}$ cubic feet[/tex]

Step-by-step explanation:

Given : The average discharge at the mouth of the Amazon River =4,900,000 cubic feet per second.

i.e. The average discharge at the mouth of the Amazon River in 1 second= 4,900,000 cubic feet

Since 1 hour = 3600 seconds

Then , the average discharge at the mouth of the Amazon River in 1 hour =

$4900000\times3600=17640000000$ cubic feet

Since , there are 2080 hours in a typical year.

Then, the average discharge at the mouth of the Amazon River in 1 year=

$2080\times17640000000\\\\=36,691,200,000,000=3.66912\times10^{13}$ cubic feet

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3 years ago