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Jobisdone [24]
3 years ago
6

How to Solve the inequality x+2<8

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Answer:

x<6

Step-by-step explanation:

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How much is 3/5 of 31/8 ?
Otrada [13]

Answer:

2.325

Step-by-step explanation:

i used a calculator ,i think i did it right lol

5 0
3 years ago
In which of the number lines does the plotted point represent a number greater than -1 1/2? Check all that apply.
Nikitich [7]

Hi!

The first number line is equals to -1\frac{1}{2}

The second number line is equals to \frac{-1}{2}

The third number line is equals to -2\frac{1}{2}

The fourth number line is equals to 2

The fifth number line is equals to 0

The sixth number line is -2\frac{3}{4}

The answer is; second, fourth and fifth number lines.

<em></em>

<em>I hope, I could help.</em>

<em>Wish Good Lessons! ^-^</em>

6 0
3 years ago
Read 2 more answers
100 decreased by 50% and 150 decreased by 60%<br><br><br> Compare
sertanlavr [38]

Answer: 60% = 60/100 = 60 ÷ 100 = 0.6. 100% = 100/100 = 100 ÷ 100 = 1.

Step-by-step explanation: Decrease number by 60% of its value. Percentage decrease = 60% × 150 New value = 150

5 0
2 years ago
What is scale factor of the two triangles ?
Arada [10]

Answer:

GKN is 3/4 of AHL

Step-by-step explanation:

Compare the similar sides. 3:4. 6:8. 15:20. All of them are equivalent to 3/4

6 0
3 years ago
Read 2 more answers
Exhibit 6-5 The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation o
hjlf

Answer:

46.18% of the items will weigh between 6.4 and 8.9 ounces.

Step-by-step explanation:

We are given that the weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.

<em>Let X =  weight of items produced by a machine</em>

The z-score probability distribution for is given by;

                Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean weight = 8 ounces

            \sigma = standard deviation = 2 ounces

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of items that will weigh between 6.4 and 8.9 ounces is given by = P(6.4 < X < 8.9) = P(X < 8.9 ounces) - P(X \leq 6.4 ounces)

   P(X < 8.9) = P( \frac{  X -\mu}{\sigma} < \frac{  8.9-8}{2} ) = P(Z < 0.45) = 0.67364  {using z table}

   P(X \leq 70) = P( \frac{  X -\mu}{\sigma} \leq \frac{  6.4-8}{2} ) = P(Z \leq -0.80) = 1 - P(Z < 0.80)

                                                 = 1 - 0.78814 = 0.21186

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.45 and x = 0.80 in the z table which has an area of </em>0.67364<em> and </em>0.78814<em> respectively.</em>

Therefore, P(6.4 < X < 8.9) = 0.67364 - 0.21186 = 0.4618 or 46.18%

<em>Hence, 46.18% of the items will weigh between 6.4 and 8.9 ounces.</em>

8 0
3 years ago
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