Answer:
2/7, 4/7, 1/2, 5/6, 3/8
Step-by-step explanation:
i dont know if its correct
<h3><u>
Answer:</u></h3>
<h3><u>
Step-by-step explanation:</u></h3>
<em>There can be many ways to find the number.</em><em> I have found the number with the help of fractions and multiplication. </em><em>Below is the solution to your problem.</em>
- 80 = 20/100
- => 5 x 80 = 20 x 5/100
- => 400
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Conclusion:</u></h3>
<em>Hence, 80 is 20% of 400. </em><em>I hope my method helped you.</em>
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2
= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)
Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)
Answer:
(f o h)(x) = -10x + 32
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x³ + 8
h(x) = ∛(12 - 5x)
(f o h)(x) is f(h(x))
<u>Step 2: Find Composite Function</u>
- Substitute: (f o h)(x) = 2(∛(12 - 5x))³ + 8
- Evaluate: (f o h)(x) = 2(12 - 5x) + 8
- Distribute 2: (f o h)(x) = 24 - 10x + 8
- Combine like terms: (f o h)(x) = -10x + 32
And we have our final answer!
