(x+5) (×+5)=49. I need to know what x is, how do I solve this?

Mathematics

1 answer:

Archy [21]3 years ago

4 0

$(x+5)^2=49$
squaer root both sides
x+5=+/-7
minus 5 both sides
x=-5+/-7
x=-5+7=2
x=-5-7=-12

x=2 or -12

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$\displaystyle\int_0^{2\pi}(36\sin t\cos t\,\mathbf i+(25-30\cos t)\,\mathbf j+42\sin t\,\mathbf k)\cdot(-6\sin t\,\mathbf i+6\cos t\,\mathbf j+6\sin t\,\mathbf k)\,\mathrm dt$
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