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Firdavs [7]
2 years ago
12

I need help with this question.. Please

Mathematics
1 answer:
Dvinal [7]2 years ago
6 0

\text{If}\ \triangle ABC\cong\triangle DE F, \text{then}\\\\m\angle A=m\angle D,\ m\angle B=m\angle E\ \text{and}\ m\angle C=m\angle F\\\\\text{Therefore we have the equation:}\\\\8x-1=87\qquad\text{add 1 to both sides}\\\\8x=88\qquad\text{divide both sides by 8}\\\\\boxed{x=11}\\\\\text{We know, the sum of measures of the angles in a triangle is 180}^o.\\\\\text{Therefore:}\\\\m\angle F=180^o-(42^o+87^o)\\\\m\angle F=180^o-129^o\\\\m\angle F=51^o\\\\\text{We have the equation:}

3y=51\qquad\text{divide both sides by 3}\\\\\boxed{y=17}\\\\Answer:\ \boxed{x=11\ and\ y=17}

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If f(x) = x-1/3 and g(x) = 3x+1 what is (fog)(x)
marin [14]

Answer:

if you meant  f(x) = (x - 1) /3    then   f (g(x) ) = x

of if you meant  f(x) = x - (1/3) then  f(g (x)) =   3x + 2/3

Step-by-step explanation:

f(x) = x-1/3 and g(x) = 3x+1 what is (fog)(x)

f ( g(x) ) =  (3x + 1)  - (1/3) =   3x  + 2/3

Or

if you meant  f(x) = (x - 1) /3    then   f (g(x) ) = x

of if you meant  f(x) = x - (1/3) then  f(g (x)) =   3x + 2/3

3 0
3 years ago
Solve by Elimination/Addition<br><br> {−6x−2y=−1618x+6y=48
tia_tia [17]

Answer:

201.5x-y=-6

Step-by-step explanation:

−6x−2y=−1618x+6y=48

Collect like terms

-6x+1618x-2y-6y=-48

1612x-8y=-48

Divide through by 8

1612x/8-8y/8=-48/8

201.5x-y=-6

6 0
3 years ago
Simplify the following Questions. (IMPORTANT NOTE!!! #'s 2 AND 7 MUST BE IN SCIENTIFIC NOTATION!!!!!) 1.) (x)²(2xy³)^5 2.) (4x10
poizon [28]

Answer:

Step-by-step explanation:

Hint :

(a*b)^{m}= a^{m}b^{m}\\\\\\(a^{m})^{n}=a^{mn}\\\\\\a^{m}*a^{n}=a^{m+n}\\

1)x^{2}(2xy^{3})^{5}=x^{2}*2^{5}*x^{5}*(y^{3})^{5}\\\\\\=x^{2}*2^{5}*x^{5}*y^{3*5}\\\\=x^{2}*2^{5}*x^{5}*y^{15}\\\\=2^{5}*x^{2+5}*y^{15}\\\\=2^{5}x^{7}y^{15}

2) (4x10^{8})^{2}=4^{2}*x^{2}*(10^{8})^{2}\\\\=16*x^{2}*10^{8*2}\\\\=1.6*10*x^{2}*10^{16}\\\\=1.6x^{2}*10^{16+1}\\\\=1.6x^{2}10^{17}

3)(-h^{4})^{5}=(-h)^{4*5}=-h^{20}\\\\\4)(3xy^{3})^{2}(xy)^{6}=3^{2}x^{2}(y^{3})^{2}x^{6}y^{6}\\\\=9x^{2}y^{3*2}x^{6}y^{6}\\\\\\=9x^{2}y^{6}x^{6}y^{6}\\\\=9x^{2+6}y^{6+6}\\\\=9x^{8}y{12}\\\\\\

5) (p^{9})^{-2}=p^{9*-2}=p^{-18}\\\\\\6)(5k^{2})^{3}=5^{3}(k^{2})^{3}=625k^{6}\\\\7)(7x10^{5})^{2}=7^{2}x^{2}(10^{5})^{2}\\\\=49x^{2}10^{5*2}\\\\=4.9*10^{1}x^{2}10^{10}\\\\=4.9x^{2}10^{10+1}\\\\=4.9x^{2}10^{11}

8)x^{3}(-x^{3}y)^{2}=x^{3}*(-x^3})^{2}y^{2}\\\\\\=x^{3}*(-1)^{2}*x^{2*3}y^{2}\\\\=x^{3}*1*x^{6}y^{2}=x^{3+6}y^{2}\\\\=x^{9}y^{2}\\\\\\9)w^{5}(w^{2})^{-4}=w^{5}w^{2*-4}\\\\=w^{5}w^{-8}\\\\=w^{5-8}=w^{-3}\\\\=\frac{1}{w^{3}}\\\\\\10) (2x^{5})^{4}=2^{4}x^{5*4}\\\\=2^{4}x^{20}\\\\=16x^{20}

5 0
3 years ago
Suppose you deposit $12.50 into your savings account each week for 4 weeks and then withdraw $4.80 each week for the next two we
monitta

Answer:

The total change in the amount of money in my account is $ 9.60

Step-by-step explanation:

Given:

Amount of money deposited each week, A_{d}=\$12.50

Amount of money withdrawn each week, A_{w}=\$4.80

∴ Amount of money deposited in 4 weeks, A_{dT}=A_{d}\times 4=12.50\times 4 = \$50

∴ Amount of money withdrawn in 2 weeks, A_{wT}=A_{w}\times 4=4.80\times 2 = \$9.6

Now, amount of money left in the account is the difference of the two amounts.

So, amount left = A_{dT}-A_{wT}=50-9.6=\$40.4

Therefore, the total change in the amount of money in my account is given as:

Total change = Initial amount after 4 weeks - Final amount in the account.

Total change = $ 50 - $40.4 = $ 9.6

7 0
3 years ago
Changing the order of addends on a problem with more than two atoms always changes the answer
Temka [501]
True..... I think......
6 0
2 years ago
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