On the last three physics exams a student scored 89, 87, and 92. What score must the student earn on the next exam to have an av
1 answer:
Answer:
For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Step-by-step explanation:
The score of students in last 3 exams = 89 , 87 and 92
Let us assume the marks scored by the student in last exam = k
The average of marks should be above 90.
Now,
Sum of all 4 paper's marks = 89 + 87 + 92 + k = 268 + k
Also, 90 < Average
Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
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Any changes inside the f(x) notation impacts x-values of points on the graph.
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8. y=f(x+6)
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9. y=-f(x)
Inside change, impacts y-values. Every y-value will be given the opposite signs. Negatives become positive and positives become negative. This will flip your graph over the x-axis.
10. y = f(-x) + 5
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11. y = - 3 f(x-3)
There are three things happening. A negative on the outside, multiplying by 3 on the outside, and subtracting 3 inside. What will each of those do individually? Take a shot on this one and let me know what you think.
12. y = 1/2 f( 1/2 x )
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