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slavikrds [6]
4 years ago
14

Write an expression for the model. Find the sum. options: a) 2 + (–3); 1 b) –3 + 2; 5 c) 2 + 3; 5 d) 2 + (–3); –1

Mathematics
1 answer:
Dima020 [189]4 years ago
5 0

Answer:

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

Step-by-step explanation:

When adding integers (positive and negative whole numbers), there are three cases:

  • Positive and positive increases and sum is positive. Ex. 4 + 6 = 10
  • Positive and negative where you subtract and take the sign of the larger number. Ex. 3 + -8 = -5 or -3 + 8 = 5
  • Negative and negative decrease and the sum if negative. Ex. -4 + -6 = -10.

Use these rules to simplify each expression.

a) 2 + (–3) = -1 not 1     FALSE

b) –3 + 2 = -1 not 5      FALSE

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

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Answer:

SA=234.8\ yd^2

Step-by-step explanation:

we know that

The surface area of the regular pyramid is equal to the area of the triangular base plus the area of its three triangular lateral faces

step 1

Find the area of the triangular base

we know that

The triangular base is an equilateral triangle

so

The area applying the law of sines is equal to

A=\frac{1}{2}(14^2)sin(60^o)

A=\frac{1}{2}(196)\frac{\sqrt{3}}{2}

A=49\sqrt{3}=84.87\ yd^2            

step 2

Find the area of its three triangular lateral faces

A=3[\frac{1}{2}bh]

we have

b=14\ yd

Find the height of triangles

Applying the Pythagorean Theorem

10^2=(14/2)^2+h^2

solve for h

100=49+h^2

h^2=100-49

h=\sqrt{51}\ yd

substitute

A=3[\frac{1}{2}(14)\sqrt{51}]      

A=149.97\ yd^2

step 3

Find the surface area

Adds the areas

SA=84.87+149.97=234.84\ yd^2

Round to the nearest tenth

SA=234.8\ yd^2

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3 years ago
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32 ounces of water in a glass someone drink 55% how many ounces left in glass
borishaifa [10]
Hello!

Convert 55% to a decimal by dividing it by 100.

55 ÷ 100 = 0.55

Next, multiply the total amount of ounces of water by this decimal.

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32 - 17.6 = 14.4

ANSWER:

14.4 ounces of water are left in the glass.
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