True or False?<br> k = 3 over 4 is a solution to the inequality 12k + 2

He temperature was -13 degrees and then rose 9 degrees.<br> -13 + 9<br> 13 + 9<br> 9 - (-13)

Aleonysh [2.5K]

Answer:

-13 + 9

Step-by-step explanation:

if you have -13° and then it rises 9°, it will be added since it’s rising and rise can be a way of addition. so -13 + 9 is your answer

3 0

2 years ago

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Which choices are equivalent to the fraction below check all the apply ""24" over 30

user100 [1]

Answer:

c) The reduced form of the given fraction $\frac{24}{30} = \frac{4}{5}$

Step-by-step explanation:

Here, the given expression is "24 over 30".

The given expression is is equivalent to $\frac{24}{30}$

Now by Prime Factorization:

24 = 2 x 2 x 2 x 3

30 = 2 x 3 x 5

⇒ The common factors in 24 and 30 is 2 x 3 = 6

So, $\frac{24}{30} = \frac{2 \times 2 \times 2 \times 2 \times 3}{2 \times 3 \times 5} = \frac{6 \times 4}{6 \times 5} = \frac{4}{5}$

Hence the reduced form of the given fraction $\frac{24}{30} = \frac{4}{5}$

6 0

3 years ago

Need help it’s easy

defon

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3 0

2 years ago

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Hailey bought 3 pounds of apples for $7.70. How much did she pay per pound?

7nadin3 [17]

2.57 is the anwser. it comes out to be 2.56666667 which woukd round up to 2.57

6 0

3 years ago

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A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po

igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b) Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c) $z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation

$X_{1}=170$ represent the number of people with the characteristic 1

$X_{2}=110$ represent the number of people with the characteristic 2

$n_{1}=200$ sample 1 selected

$n_{2}=150$ sample 2 selected

$p_{1}=\frac{170}{200}=0.85$ represent the proportion estimated for the sample 1

$p_{2}=\frac{110}{150}=0.733$ represent the proportion estimated for the sample 2

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

a.State the decision rule.

For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c. Compute the value of the test statistic.

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0

3 years ago

True or False? k = 3 over 4 is a solution to the inequality 12k + 2 < 12.