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3 years ago

An expression is given.

Mathematics

1 answer:

igomit [66]3 years ago

4 0

Answer:

None of those

Step-by-step explanation:

$a) -1xy + 74 \neq -2y + 32 x + 74\\\\ b) 32x - 2(y + 72) = 32x -2y -144\\32x -2y -144 \neq -2y + 32 x + 74\\ \\ c) -14y + 32(y +x) = -14y + 32y+32x \\ -14y + 32y+32x\neq-2y + 32 x + 74\\ \\d) -2y + 12 (3x + 72) = -2y + 36x+864\\-2y + 36x+864\neq -2y + 32 x + 74\\ \\e) 14(-8y + 6x + 7) = -112y +84x+98\\ -112y +84x+98 \neq -2y + 32 x + 74$

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Lesechka [4]

Answer:

(a) 0.675

(b) 0.3

Step-by-step explanation:

$P(R) = 90\% = 0.9$ (Probability of functional red)

$P(\sim R) = 90\% = 1 - 0.9 = 0.1$ (Probability of non-functional red)

$P(G) = 75\% = 0.75$ (Probability of functional green)

$P(\sim G) = 1 - P(G) = 1 - 0.75 = 0.25$ (Probability of non-functional green)

(a) The probability the board is functional is the probability that the red and the green resistors are functional.

$P(\text{board is functional}) = P(R\cap G) = P(R) \times P(G) = 0.9\times0.75 = 0.675$

(b) The probability that exactly one of the resistors chosen is functional is the probability that either red is functional and green is not or green is functional and red is not.

$P(\text{exactly one is functional}) = P((R\cap \sim G) \cup (G\cap \sim R))$

$P(\text{exactly one is functional}) = P(R\cap \sim G) + P(G\cap \sim R) = (P(R) \times P(\sim G)) + (P(G) \times P(\sim R))$

$P(\text{exactly one is functional}) = (0.9 \times 0.25) + (0.75 \times 0.1) = 0.225 + 0.075 = 0.3$

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Fittoniya [83]

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