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NikAS [45]
4 years ago
6

What is VAT @ 13.5% on 157.46

Mathematics
1 answer:
weeeeeb [17]4 years ago
8 0
20.89 ................
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A triangular prism has height 8 units. The base of the prism is shown in the image. What is the volume of the prism? Round your
Nadya [2.5K]

Answer:

Ypu have to multiply all the sides to find your answer

Step-by-step explanation:

6 0
3 years ago
Jack broke apart 5 times 216 as (5 times 200) + (5 times 16) to multiply mentally. what strategy did he use?
Klio2033 [76]
Jack used distributive property
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for every 5 pounds of pasta served , 15 people can be fed. how many people can be fed with 4 pounds of pasta?
Sidana [21]

Answer:

12

Step-by-step explanation:

its direct proportion. 15 divided by 5 is 3 so you must multiply 3 by 4 to get the amount of people, which is 12

7 0
3 years ago
A 15 kilogram object is suspended from the end of a vertically hanging spring stretches the spring 1/3 meters. At time t = 0, th
Yuri [45]

Answer:

15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

y(0)=0, y'(0)=0

Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

k = \frac{F_{r}}{y} = \frac{mg}{y} = \frac{15 Kg (9.81 \frac{m}{s^{2} } )}{\frac{1}{3} m}  = 441.45 \frac{N}{m}

Now we apply Newton's 2nd Law and obtaint that...

F_{r} (t) ± F(t) = ma(t)

F_{r} (t) = ky(t) = 441.45y(t)

F(t) = 170 cos(5t)

m = 15 kg

a(t) = \frac{d^{2}y(t)}{dt^{2} }

Finally... 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

6 0
3 years ago
There are two cookie jars: jar 1 contains two chocolate chip cookies and three plain cookies, and jar 2 contains one chocolate c
vesna_86 [32]

Answer:

P = 0.55   or  55 %

Step-by-step explanation:

First step:  Fred has probability of 0,5 when chossing jar 1 or jar 2

Second step : The probability of chossing one chocolate chp cookie in jar 1 is 3/5 and from the jar 2 is 1/2

Then the probability of Fred to get a chocolate chip cookie is

P ( get a chocolate chip cookie ) =( 0.5 * 3/5) +( 0.5* 1/2)

P = 0.3 + 0.25

P = 0.55   or  55 %

8 0
3 years ago
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