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3 years ago

13

A machine can seal 179 envelopes in 1 minute. If there are 1,440 minutes in a 24-hour day,how many envelopes can the machine sea

l in 1 day?

1 answer:

ANTONII [103]3 years ago

8 0

257760 envelopes the machine seal in 1 day<span />

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Can someone please help convert these so they have the same denominator??

ratelena [41]

The LCM of the denominators is 120. In other words, the denominators can multiply to 120.

3 * 40 = 120

40 * 2 = 80

Tigers: P = 80/120

24 * 5 = 120

24 * 4 = 96

Redbirds: P = 96/120

8 * 15 = 120

3 * 15 = 45

Bulldogs P = 45/120

60 * 2 = 120

60 * 1 = 60

Titans P = 60/120

Answer

Tigers: P = 80/120

Redbirds: P = 96/120

Bulldogs: P = 45/120

Titans: P = 60/120

5 0

2 years ago

If Linda can walk 6 miles in 80 minutes,

Marta_Voda [28]

I think it is 4.5 miles per hour

8 0

2 years ago

Pls answer this with a picture showing the correct box plot

faust18 [17]

Answer/Step-by-step explanation:

To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.

Given, {2, 3, 5, 6, 10, 14, 15},

Minimum value = 2

Median = middle data point = 6

Q1 = 3 (the middle value of the lower part of the data set before the median)

Q3 = 14 (middle value of the upper part of the data set after the median)

Maximum value = 15

If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.

See the attachment below for the correct box plot.

3 0

2 years ago

Solve the equation.

blondinia [14]

Answer: 12

Step-by-step explanation:

6c + 11= 2c + 59

Collect like terms

6c - 2c = 59 - 11

4c = 48

c = 48/4

c = 12

4 0

2 years ago

Read 2 more answers

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

2 years ago

Read 2 more answers