Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 
is 
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
Substituting m1 we get m2 as
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
Answer:
3
Step-by-step explanation:
Answer:
C.76
Step-by-step explanation:
2x= 19
x= 9.5
8x =?
8(9.5)= ?
76= ?
Answer:
y = 1/3x - 2
Step-by-step explanation:
We are asked to find the equation of a line with two points
Step1: find the slope
m = (y_2 - y_1)/(x_2 - x_1)
( 0 , -2) (6 , 0)
x_1 = 0
y_1 = -2
x_2 = 6
y_2 = 0
Insert the values
m = ( 0 - (-2)/ (6 - 0)
m = ( 0 + 2)/(6 - 0)
m = 2/6
m = (2/2)/(6/2)
m = 1/3
Step 2 : substitute m into the equation of line
y = mx + c
y = intercept y
m = slope
x = intercept x
c = intercept
y = 1/3x + c
Step 3: sub any of the two points
Let's pick ( 6 ,0)
x = 6
y = 0
Insert the values into
y = 1/3x + c
0 = 1/3(6) + c
0 = 1*6/3 + c
0 = 6/3 + c
0 = 2 + c
c = 0 - 2
c = -2
Sub c = -2
y = 1/3x - 2
The equation of the line is
y = 1/3x - 2
