<span>Let f(n) = 2n + 5. Then we must simply calculate (f1), f(2), ..., (f12). And we have that f(1) = 2*1 + 5 <=> f(1) = 7; f(2) = 2*2 + 5 <=> f(2) = 9; f(3) = 2*3 + 5 <=> f(3) = 11. And so on. It's easy to see that the rest of the results will be 13, 15, 17, 19, 21 and so on. So the summation will be S = 7 + 9 + 11 +... + 29 <=> S = 216</span>
So dad=28
cindy=2
so 28-2=diffirance in age=26
A. dad-26=cindy
cindy=dad-26
dad=cindy+26
so since cindy=18
dad=18+26=44
B. if dad =42=cindy+26 so
42=x+26
subtract 26 from both sides
16=x
cindy =16 if dad =42
C. so the number of years apart they will be will always be 26 (until one of them dies)
Answer:
A)
Step-by-step explanation:
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