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RideAnS [48]
3 years ago
10

How do I solve for X?

Mathematics
1 answer:
elena-s [515]3 years ago
7 0
The distance from the external point ^2 = The external segment of the secant * the full length of the secant.
tangent distance = 6
External portion of the secant = 3
Full length of the secant = x + 3

6^2 = 3*(x + 3) Remove the brackets. 
36 = 3x + 9  Subtract 9 from both sides.
36 - 9 = 3x
27 = 3x Divide by 3
x = 9  <<<<<<<Answer.
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Read 2 more answers
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

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3 years ago
Can someone please help me
babymother [125]

Answer:

Its a i just took the test

Step-by-step explanation:

4 0
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Write 6/9=a/b in simplest form
kobusy [5.1K]

Answer:

2/3 = a/b

Step-by-step explanation:

6/9 = a/b

2/3 = a/b

8 0
3 years ago
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