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3 years ago

BRAINLIESTTT ASAP!!! PLEASE HELP ME :))

Chemistry

1 answer:

garri49 [273]3 years ago

6 0

Answer:

Multiply 1.25 by 0.04 and divide the result obtained by 1,000

Explanation:

Given: [1 gram = 0.04 ounce, 1 liter = 1,000 milliliter]

1.25 x 0.04 = 0.05 oz

Therefore, 0.05 per 1,000 milliliter

0.05 ÷ 1,000 = 0.00005 oz

Therefore, the density of the gas is 0.00005 oz/mL

Hope this helps! :)

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How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)

7nadin3 [17]

Answer:

The answer to your question is V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

6Ca + 2NH₃ ⇒ 3CaH₂ + Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

CaH₂ = 40 + 2 = 42 g

42 g ------------------ 1 mol

2.65 g -------------- x

x = (2.65 x 1)/42

x = 0.063 moles

2.- Calculate the moles of NH₃

2 moles of NH₃ --------------- 3 moles of CaH₂

x --------------- 0.063 moles

x = (0.063 x 2) / 3

x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

= 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

PV = nRT

-Solve for V

V = nRT / P

-Substitution

V = (0.042)(0.082)(296) / 3.2

-Simplification

V = 1.019 / 3.2

-Result

V = 0.32 L

7 0

3 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl 2 solution:

4vir4ik [10]

Answer:

Explanation:

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2 years ago

Is a burning log an exothermic or endothermic event if the log is the system?

denpristay [2]

It would be endothermic because the log is in the system.

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2 years ago

What is solubility curves

love history [14]

Answer:

Explanation:

A solubility curve is a graph of solubility, measured in g/100 g water, against temperature in °C. Solubility curves for more than one substance are often drawn on the same graph, allowing comparisons between substances

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2 years ago