Answer:
Option c, Two atomic orbitals combine to form one molecular orbital
Explanation:
Molecular orbitals are formed by linear combination of atomic orbitals.
Some of the important facts of molecular orbital theories are as follows:
- No. of the molecular orbitals formed are equal to the no. of atomic orbitals participated.
- Half of the molecular orbitals are bonding molecular orbitals and half of the molecular orbitals are anti bonding molecular orbitals.
- Anti bonding molecular orbitals have energy higher than participating atomic orbitals.
- Bonding molecular orbitals have energy lower than participating atomic orbitals.
- Molecular orbitals are that region in the molecule where electrons are most likely to found.
So, among given, option c which is 'atomic orbitals combine to form one molecular orbital' is incorrect.
(C) neon (atomic number 10)
Explanation:
The atom that is chemically inert is Neon with an atomic number of 10.
An atom is chemically inert if it does not willingly take part in chemical reaction.
Atoms takes part in chemical reactions in order to attain a stable configuration as seen in the noble gases.
In the noble gases every enable level is completely filled with the appropriate number of electrons.
- The noble gases are He, Ne, Ar, Kr, Xe
- These elements do not react with others.
- From the given option, Neon is a noble gas and therefore inert.
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The first element discovered through synthesis was technetium<span>—its discovery being definitely confirmed in 1936. Hope that helps.</span>
The balanced equation for the ionization of the weak base pyridine,C5H5N in water, H2O
C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)
<h3>What is the balanced equation for the ionization?</h3>
Generally, Pyridine is characterized by a ring structure, in this characteristic ring structure N is sp2 hybridized, hence creating a lone pair present on N so s - character is more, as well as lone pair, is present.
Therefore, Considering The following functions of the equation:weak base pyridine,C5H5N in water, H2O
We write the balanced equation for the ionization as
C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)
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