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Nikitich [7]
3 years ago
14

Write an equation of a line in point slope form that has a slope of -3 and passes through the point (3, -4).

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0

1) Point-slope form

(y-y1)=m(x-x1)

m= - 3,

point (3,-4), so x1 = 3, y1 = - 4.

(y+4)= -3(x- 3)

2)Point-slope form

(y-y1)=m(x-x1)

m= - 3/4,

point (4,5), so x1 = 4, y1 = 5.

(y-5)= - 3/4(x-4)

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Answer:

Step-by-step explanation:

P = 4 + 6 + (3y - 2)      Remove the brackets

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Step-by-step explanation:

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aleksandr82 [10.1K]

Answer:

Point of intersections are (0, -7) and (5, -2).

Step-by-step explanation:

From the graph attached,

A straight line is intersecting the circle at the two points (0, 7) and (5, -2).

Now solve algebraically,

Equation of the line → y = x - 7 -------(1)

Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)

By substituting the value of y from equation (1) to equation (2)

(x - 5)² + (x - 7 + 7)² = 25

(x - 5)² + x² = 25

x² - 10x + 25 + x² = 25

2x² - 10x = 0

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x(x - 5) = 0

x = 0, 5

From equation (1),

y = 0 - 7 = -7

y = 5 - 7 = -2

Therefore, point of intersections are (0, -7) and (5, -2).

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Step-by-step explanation:


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