2 years ago

Consider the intial value problem 2ty' = 4y, y(1) = -2.

Mathematics

1 answer:

Colt1911 [192]2 years ago

4 0

Answer:

y+-2t^2

Step-by-step explanation:

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Step-by-step explanation:

Given

See attachment for triangles

Solving (a)

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$Adjacent = 5$

$Hypotenuse = 13$

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$\cos B = \frac{5}{13}$

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