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3 years ago

Ch4o(l)+o2(g)→ express your answer as a chemical equation. identify all of the phases in your answer.

1 answer:

4 0

CH4O(I) + O2(g) = CO2(g) + H2O(g) 2 CH4O(I) + 3 O2(g) = 2 CO2(g) + 4 H2O(g) it is the double reaction. CH4O(I): Molar mass is 32.0419 g/mol C - Carbon; H - Hydrogen; O - Oxygen O2(g): Molar mass is 31.99880 Â± 0.00060 g/mol O - Oxygen CO2(g): Molar mass is 44.0095 g/mol C - Carbon: O - Oxygen H2O (g): Molar mass is 18.01528 Â± 0.00044 g/mol H - Hydrogen; O - Oxygen

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When an acid and a base react, a particular type of salt is formed. This is an example of what type of reaction?

Tom [10]

Answer:

Chemical

Explanation:

A chemical change is formed because the state of the substances can't be changed to its previous state. Therefore it's a chemical change only.

6 0

4 years ago

Read 2 more answers

What is the molarity of a solution that is composed of 10 grams of Sodium Chloride ( NaCl) dissolved in 3.50 L of water

Gennadij [26K]

Answer: The molarity of solution will be 0.049 M

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (L)}}$

We are given:

Given mass of sodium chloride = 10 g

Molar mass of sodium chloride = 58.44 g/mol

Volume of solution = 3.50 L

Putting values in above equation:

$\text{Molarity of NaCl}=\frac{10 g}{58.44g/mol\times 3.50}\\\\\text{Molarity of NaCl}=0.049M$

Hence, the molarity of solution will be 0.049 M

6 0

3 years ago

Draw the mechanism for the sn1 reaction for step 2 in the procedure

Crazy boy [7]

Do u have a picture plz

6 0

3 years ago

If a stock solution of 20.0 g of sugar per 100. ml of solution is available, how much of this stock is needed to prepare 10.0 ml

Vladimir79 [104]

You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.

We can use the dilution formula

V_1C_1 = V_2C_2

where

V represents the volumes and

C represents the concentrations

We can rearrange the formula to get

V_2 = V_1 × (C_1/C_2)

V_1 = 10.0 mL; C_1 = 5.00 g/100. mL

V_2 = ?; ____C_2 = 20.0 g/100. mL

∴ V_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250

= 2.50 mL

3 0

3 years ago

Which statement defines the enthalpy of hydration?

Anettt [7]

The law of conservation of energy

7 0

3 years ago