Answer:
The equillibrium constant Kc = 11.2233
Explanation:
Step 1:
aA + bB ⇔ cC + dD
with a, b, c and d = coefficients
Kc = equillibrium constant =( [C]^c [D]^d ) / ( [A]^a [B]^b)
Concentration at time t
[A] = 0.300 M
[B] =1.10 M
[C] = 0.450 M
Change :
A: -x
B: -2x
C: -x
The following reaction occurs and equillibrium is established
A + 2B ⇔ C
[A] = 0.110M
[B] = ?
[C] = 0.640 M
For A we see that after change: 0.3 -x = 0.11
Then for B we have 1.1 - 2x = ? ⇒ 1.1 -2 *0.19 = 0.72
This gives us for the equillibrium constant Kc = [C] / [A][B] ²
Kc = 0.64 / (0.11) * (0.72)² = 11.2233
Answer is: empirical formula for compound is C₂H₆O.
m(CO₂) = 1,6003 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 1,6003 g ÷ 44 g/mol.
n(CO₂) = 0,0364 mol.
n(CO₂) = n(C).
m(C) = 0,0364 mol · 12 g/mol = 0,4368 g.
m(H₂O) = 0,9827 g.
n(H₂O) = 0,9827 g ÷ 18 g/mol.
n(H₂O) = 0,0546 mol.
n(H) = 2 · n(H₂O) = 0,1092 mol.
m(H) = 0,1092 mol · 1 g/mol = 0,1092 g.
m(O) = 0,8376 g - 0,4368 g - 0,1092 g = 0,2916 g.
n(O) = 0,2916 g ÷ 16 g/mol = 0,0182 mol.
n(C) : n(H) : n(O) = 0,0364 mol : 0,1092 mol : 0,0182 mol.
n(C) : n(H) : n(O) = 2 : 6 : 1.
Answer:
In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.
Explanation:
The percent by weight (w/w%) of sugar in soda : 6.216%
<h3>Further explanation</h3>
Given
mass of sugar = 23 g
total mass = 370 g
Required
the percent weight
Solution
%weight = (mass of solute : mass of solution) x 100%
solute = sugar
solution = solvent + solute = water + sugar
percent weight of sugar in soda :
= (23 : 370) x 100%
= 6.216 %
