Answer:
The empirical formula of the compound is = 
The name of the compound is potassium bromate.
Explanation:
Mass of potassium = 4.628 g
Moles of potassium = 
Mass of bromine = 9.457 g
Moles of bromine = 
Mass of oxygen = 5.681 g
Moles of oxygen = 
For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:
Potassium :
Bromine;
Oxygen ;
The empirical formula of the compound is =
The name of the compound is potassium bromate.
25.2 / 34.6 x 100
which would get you 73%
if you found my answer helpful pls give brainliest
The balanced equation for the neutralisation reaction is as follows
2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O
stoichiometry of H₃PO₄ to H₂O is 2:6
number of H₃PO₄ moles reacted - 0.24 mol
if 2 mol of H₃PO₄ form 6 mol of H₂O
then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O
therefore 0.72 mol of H₂O are formed
Kinetic energy is associated with the motion of an object.
Since the object is at rest on the ground, its velocity is zero.
Since kinetic energy is directly proportional to the square of velocity, kinetic energy of the ball on the ground is zero.
