Answer: Option (3) is the correct answer.
Explanation:
When a more reactive element or atom replaces a less reactive atom then this type of reaction is known as single displacement reaction.
In the given reaction, potassium iodide reacts with fluorine and results in the formation of potassium fluoride and iodine.
Here, fluorine being more reactive displaces iodine from potassium iodide.
Therefore, it is a single replacement or displacement reaction.
55.9 kPa; Variables given = volume (V), moles (n), temperature (T)
We must calculate <em>p</em> from <em>V, n</em>, and <em>T</em>, so we use <em>the Ideal Gas Law</em>:
<em>pV = nRT</em>
Solve for <em>p</em>: <em>p = nRT/V</em>
R = 8.314 kPa.L.K^(-1).mol^(-1)
<em>T</em> = (265 + 273.15) K = 538.15 K
<em>V</em> = 500.0 mL = 0.5000 L
∴ <em>p</em> = [6.25 x 10^(-3) mol x 8.314 kPa·L·K^(-1)·mol^(-1) x 538.15 K]/(0.5000 L) = 55.9 kPa
Answer:
2-methoxybutane
Explanation:
This reaction is an example of Nucleophilic substitution reaction. Also, the reaction of (S)-2-bromobutane with sodium methoxide in acetone, is bimolecular nucleophilic substitution (SN2). The reaction equation is given below.
(S)-2-bromobutane + sodium methoxide (in acetone) → 2-methoxybutane
B) Mg is the alkaline earth metal w/12 protons so following the periodic table to the halogen in the same period is
Cl: Chlorine
C) The Neutral noble has w/ 18 electrons is argon so the metal in the same row is
Na: Sodium
