Question

12. The equations of two lines are 6x-y=4 and y= 4x+2. What is the value of x in the

Answer 1

For this case we have the following system of equations:

$6x-y = 4\\y = 4x + 2$

We substitute the second equation in the first:

$6x- (4x + 2) = 4$

We eliminate the parenthesis taking into account that:

$- * + = -\\6x-4x-2 = 4$

We add similar terms:

$2x-2 = 4\\2x = 4 + 2\\2x = 6\\x = \frac {6} {2}\\x = 3$

We find the value of the variable "y":

$y = 4 (3) +2\\y = 12 + 2\\y = 14$

Thus, the solution of the system is given by:

$(x, y) :( 3,14)$

Answer:

$(x, y) :( 3,14)\\x=3\\y=14$