Question

A conductor carrying a current I = 14.6 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A magnetic force per unit length of 0.119 N/m acts on the conductor in the negative y direction.
(a) Determine the magnitude of the magnetic field in the region through which the current passes.T
(b) Determine the direction of the magnetic field in the region through which the current passes.+x direction −x direction +y direction −y direction +z direction −z direction

Answer 1

Answer

Given,

Current, I = 14.6 A

magnetic force per unit length = 0.119 N/m

Magnitude of magnetic field = B = ?

a) F = ILB sin θ

θ = 90°

So,

$\dfrac{F}{L}=IB$

$0.119=14.6\times B$

$B = \dfrac{0.119}{14.6}$

$B = 0.00815\ T$

$B = 8.15\ mT$

b) The direction of magnetic field is in +z direction.