Answer:
this may help you.look it once
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
I can't see the picture.
Step-by-step explanation:
0.5 of a mile - since 5,280ft = 1 mile and half of 5,280 is 2,640
No, this is not an accurate predictor because angie is not representative of the population in the algebra test.
Here,
Angie, a student in an advanced statistics course, was given an algebra test and she scored 80%.
We have to find is this an accurate predictor.
What is Accurate predictor?
Accurate predictor describes whether the predicted values match the actual values of the target field within the incertitude due to statistical fluctuations and noise in the input data values.
Here,
Angie is the student of an advanced statistics course but she gives the algebra test and scored 80%.
We know that the advanced statistics is the higher level of math so it is not an accurate predictor.
Because, An accurate predictor should be applied when the person is 100% confirmed to the related thing. So in the given situation, the student is not 100% confirm.
Hence, this is not an accurate predictor because Angie is not representative of the population in the algebra test.
Learn more about the Accurate predictor visit:
brainly.com/question/25955478
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