Which of these is an example of a literal equation?

The area of a rectangle is 72 cm². The length of the rectangle is 6 cm longer than the width.

muminat

Area =72 sq. cm

length = x+6

Width = x

l×b = Area
(x+6)x =72
x2 +6x=72
x2+6x-72=0
x2+12x-6x-72=0
x (x+12) -6 (x+12)=0
(x+12) ( x-6) =0
x=-12, x=6

since width can't be negative , the answer is x=6.

therefore, the width is 6cm

8 0

3 years ago

Day 1 Michael ran 5 miles day 2 Michael ran 2 miles day 3 Michael ran 7 miles day 4 Michael ran 3 miles how many more miles did

Nuetrik [128]

Answer:

5 And there is extra info.

Step-by-step explanation:

Day 3= 7 miles.

Day 2=2 miles.

7-2= 5

6 0

3 years ago

How many 2-digit positive integers are there such that the product of the product of their two digits is 24?

musickatia [10]

I can only list four of them:. 38, 46, 64, and 83.

5 0

3 years ago

Is one half equal to 7/12

yuradex [85]

We can chang efractions to compare them by multiplying them by 1 or x/x where x=x so

1/2=7/12?
make bottom numbers equal
2 times what=12
divide 2
what=6

1/2 times 6/6=6/12
6/12=7/12
6=7
false

so therefor it does NOT equal 7/12

3 0

3 years ago

Read 2 more answers

An individual repeatedly attempts to pass a driving test. Suppose that the probability of passing the test with each attempt is

vladimir1956 [14]

Answer:

a) Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

b) $P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

c) $P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number of trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Part a

Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

Part b

We want this probability:

$P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

We find the individual probabilities like this:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

Part c

For this case we want this probability:

$P(X \geq 5)$

And we can use the complement rule like this:

$P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

3 0

3 years ago

Which of these is an example of a literal equation?​

Which of these is an example of a literal equation?