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Margaret [11]
3 years ago
14

Find the distance between the points (-1,-7) and (8,-9). The answer must be a whole number or a fully simplified radical express

ion do not round up
Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

The answer is

<h2>\sqrt{85}  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-7) and (8,-9)

The distance between them is

d =  \sqrt{( { - 1 - 8})^{2}  +  ({ - 7 + 9})^{2} }  \\  =  \sqrt{ ({  - 9})^{2} +  {2}^{2}  }  \\  =  \sqrt{81 + 4}

We have the final answer as

\sqrt{85}  \:  \:  \: units

Hope this helps you

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Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
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Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
M=2, m=-1/2 is they parallel or perpendicular
emmasim [6.3K]

Answer:

perpendicular

Step-by-step explanation:

4 0
4 years ago
What is the slope of the line determined by the equation -1/2x+3/4y=0
kvasek [131]

Answer:

The slope is 2/3

Step-by-step explanation:

-1/2x+3/4y=0

To find the slope, we need to get the equation in the form y= mx+b

Add 1/2x to each side

-1/2x+ 1/2 x+3/4y=0+1/2x

3/4 y = 1/2x

Multiply  by 4/3 to isolate y

4/3 * 3/4 y = 4/3 * 1/2 x

y = 2/3 x

The slope is 2/3 and the y intercept is 0

7 0
4 years ago
I need 3 multiples of 10 that has 3 as one of the digits
d1i1m1o1n [39]
3 multiples of 10 that have 3 in them are 30, 300, and 3000
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4 years ago
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There are 24 girls on the track team. First race2/3 girl ran.only1/4 girl ran in second race. 1/6 on third race. Hiw many more g
alukav5142 [94]

Answer:

10 more girls

Step-by-step explanation:

So here 2/3 of 24 ran for first race

Then it gives us that 16 girls ran for first race.

Next, 1/4 of 24 ran for second race

That is 6 girls

The remaining girls ran for the third race,

24 - 22

2 girls

16 - 6 = 10

So for first race 10 more girls ran

5 0
3 years ago
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