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Margaret [11]
3 years ago
14

Find the distance between the points (-1,-7) and (8,-9). The answer must be a whole number or a fully simplified radical express

ion do not round up
Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

The answer is

<h2>\sqrt{85}  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-7) and (8,-9)

The distance between them is

d =  \sqrt{( { - 1 - 8})^{2}  +  ({ - 7 + 9})^{2} }  \\  =  \sqrt{ ({  - 9})^{2} +  {2}^{2}  }  \\  =  \sqrt{81 + 4}

We have the final answer as

\sqrt{85}  \:  \:  \: units

Hope this helps you

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What is the length of the rectangle?
gregori [183]

Step-by-step explanation:

area \: of \: rectangle \:  = 60 \:  {yards}^{2}  \\  \therefore \: (w + 4) \times \: w = 60\\  \\  \therefore \:  {w}^{2}  + 4w -60 = 0 \\  \\  \therefore \: {w}^{2}  + 10w - 6w -60 = 0 \\  \\   \therefore \: w({w} + 10) - 6(w  + 10)= 0 \\  \\  \therefore \: ({w} + 10) (w- 6)= 0 \\ \therefore \: {w} + 10 = 0 \: or \: w- 6 = 0 \\  \therefore \: {w}   = -  10  \: or \: w =  6  \\  \because \: sides \: of \: rectangle \: cant \: be \: negative \\  \therefore \: w \neq \:    - 10 \\  \\ \therefore \: w = 6 \\  \\ \therefore \: w + 4 = 6 + 4 = 10 \\  \\ length \: of \: rectangle \:  = 10 \: yards.

4 0
3 years ago
A 12-meter ladder leans against a building forming a 30° angle with the building.
KatRina [158]

Answer:

will show you two (2) ways to solve this problem.

A diagram is needed to see what is going on....

 

Without loss of generality (WLOG)

The wall is on the right. The ladder leans against the wall

with a POSITIVE slope, from SW to NE (quadrant 3 to quadrant 1).

The measure from the bottom of the ladder to the wall is 6.

 

 

Option 1:

 

The ladder, ground and wall form a right triangle.

 

The hypotenuse (ladder) is 14 feet.

 

 The bottom of the ladder is 6 feet from the wall,

  so the base of this right triangle is 6 feet.

 

The top of the ladder to the ground represents

the missing leg of the right triangle.

 

The pythagorean theorem applies, which says

 6^2 + h^2 = 14^2   where h is the height

                                 of the top of the ladder to the ground

 

36 + h^2 = 196

 

 h^2 = 196 - 36

 

h^2  = 160

 

h = sqrt(160)

 

   = sqrt(16 * 10)

 

    = sqrt(16)* sqrt(10)

 

    = 4*sqrt(10) <--- exact answer

 

    = 4 * 3.16227766016838....

 

     = 12.64911....

 

    12.65 <--- rounded to 2 digits as directed

 

----------------------------------------------

Option #2: using trig

 

With respect to the angle formed by the bottom of the

ladder with the ground

  cos T = 6/14 = 3/7  

 T = inverse-cosine(3/7) = 64.623006647 degrees

 

 sin(64.623006647) = h/14

 

 h = 14*sin(64.62300647) = 12.6491106 <--- same answer                        

hope this helps

Step-by-step explanation:

5 0
2 years ago
How to write out 14x(36-12 devised by 4
Vinvika [58]
My answer would be -84
6 0
3 years ago
If 2a+4b=5 and a is equal to three times b, what is 3a?
IrinaK [193]

Answer:

3a=4.5

Step-by-step explanation:

it says that "a is equal to 3 times b", which translates to a=3b

We can substitute a as 3b in 2a+4b=5

2(3b)+4b=5

multiply

6b+4b=5

add

10b=5

divide by 10

b=1/2

since it's given that a=3b, we can multiply 1/2 by 3

a=3/2

3a is 3 times a, so we can mutiply 3(3/2)=9/2=4.5

Hope this helps!

7 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
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