Answer:
13
Step-by-step explanation:
The given expression is (3-2i)(3-2i)
This is of the form (a-b)(a+b)
This is equivalent to
, where a = 3 and b=2i
= ![\[3^{2}-(2i)^{2}\]](https://tex.z-dn.net/?f=%5C%5B3%5E%7B2%7D-%282i%29%5E%7B2%7D%5C%5D)
= ![\[9-4i^{2}\]](https://tex.z-dn.net/?f=%5C%5B9-4i%5E%7B2%7D%5C%5D)
But ![\[i^{2} = -1\]](https://tex.z-dn.net/?f=%5C%5Bi%5E%7B2%7D%20%3D%20-1%5C%5D)
= ![\[9-4*(-1)\]](https://tex.z-dn.net/?f=%5C%5B9-4%2A%28-1%29%5C%5D)
= ![\[9+4\]](https://tex.z-dn.net/?f=%5C%5B9%2B4%5C%5D)
= ![\[13\]](https://tex.z-dn.net/?f=%5C%5B13%5C%5D)
Hence the value of the expression (3-2i)(3-2i) is 13.
There is none except for eleven and that is it
A'= (1, 1)
B'=(2, -1)
C'=(3, 0)
D'=(2,1)
good luck
Answer:
D
Step-by-step explanation:
the others are wrong
Answer:
but what's the username
Step-by-step explanation:
y is this even a question