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3 years ago

What is the answer to 25/0.5?

Mathematics

2 answers:

Nookie1986 [14]3 years ago

8 0

the answer is 40......

dexar [7]3 years ago

6 0

The answer is:

25 / 0.5 = 50

Or in fraction form:

$\bf~\frac{25}{1} / \frac{1}{2} = \frac{50}{2} / \frac{1}{2} = \frac{50}{2} * \frac{2}{1} = \frac{100}{2} = 50$

Hope it helped,

BioTeacher101

(If you have any questions, feel free to ask them in the comments)

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a box holds red pens and blue pens the ratio of red pens to blue pens is 1 to 4 The box holds 12 more blue pens than red pens wh

Genrish500 [490]

Answer:

20 pens

Step-by-step explanation:

if there is 1 red pen for every 4 blue pens

then

4 red pens would have 16 blue pens with it. makes a total of 20 pens, with 12 more blue pens than red pens

7 0

3 years ago

Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 and one-t

NeTakaya

We have been given that Layana’s house is located at $(2\frac{2}{3}, 7\frac{1}{3})$ on a map. The store where she works is located at $(-1\frac{1}{3}, 7\frac{1}{3})$ .

We are asked to find the distance from Layana’s home to the store

We will use distance formula to solve our given problem.

Let us convert our given coordinates in improper fractions.

$2\frac{2}{3}\Rightarrow \frac{8}{3}$

$7\frac{1}{3}\Rightarrow \frac{22}{3}$

$-1\frac{1}{3}\Rightarrow -\frac{4}{3}$

Now we will use distance formula to solve our given problem.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of our given point in above formula, we will get:

$D=\sqrt{(\frac{22}{3}-\frac{22}{3})^2+(\frac{8}{3}-(-\frac{4}{3}))^2}$

$D=\sqrt{(0)^2+(\frac{8}{3}+\frac{4}{3})^2}$

$D=\sqrt{0+(\frac{8+4}{3})^2}$

$D=\sqrt{(\frac{12}{3})^2}$

$D=\sqrt{(4)^2}$

$D=4$

Therefore, the distance from Layana's home to the store is 4 units and option A is the correct choice.

3 0

3 years ago

Read 2 more answers

The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?

Nataly_w [17]

Answer:

$||\overrightarrow{v}||\approx14.64$

Step-by-step explanation:

The magnitude of a vector $\displaystyle \overrightarrow{v}=\langle x,y\rangle$ is $||\overrightarrow{v}||=\sqrt{x^2+y^2}$ , which essentially describes the length of the vector itself between the initial and terminal points:

$||\overrightarrow{v}||=\sqrt{x^2+y^2}\\\\||\overrightarrow{v}||=\sqrt{(10.5)^2+(10.2)^2}\\\\||\overrightarrow{v}||=\sqrt{110.25+104.04}\\\\||\overrightarrow{v}||=\sqrt{214.29}\\\\||\overrightarrow{v}||\approx14.64$