1. Since it's m - 7 you would have 7 to both sides so you would in fact have m < 13. If you double check your answer, you see that if m is say 12 (because 12 is obviously less than 13), 12 - 7 < 6
2. Again, use the same process on this problem as the first one. Add 8 to each sides because it's you're subtracting 8 from n. So you end up with n > 13. Check your answer. Say n is 14. 14 - 8 > 5
3. This one is different because you are adding 5 to p. So in order to get p by itself, you need to subtract 5 from both sides. p < 5. Say p is 4, 4 + 5 < 10.
When working with problems like these, you need to isolate the variable on one side and get it by itself.
0234576 You just need to put the numbers in order form least to greatest and leave an even number at the end.
Answer:
1. (0, 1)
Step-by-step explanation:
Put x = 0 then work out the values of y:0
y = 3^0 = 1 y-intercept is (0,1)
y = 0,25^x , y = 0.25^0 = 1
All the others are done in same way
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
