Mode = number which appears the most
The mode for your question is 5
(8-3)²-(5-2)²
Follow the PEMDAS
P-Parenthesis
E-Exponents
M/D-Multiplication/Division
A/S-Addition/Subtraction
clear the numerals in the parenthesis:
(5)²-(3)²
Now do the exponents:
=25-9
=16
Its just: (5)²-(3)²
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
The answer is B.
Step-by-step explanation:
From the interval -6 < x < 0, the line is straight which is linear equation. The line shows its going down so it will be decreasing gradient.
