The probability that mary will win a game is 0.04, so the probability that she will not win is 0.96. if mary wins, she will be g
iven $200; if she loses, she must pay $14. if x = amount of money mary wins (or loses), what is the expected value of x? (round your answer to the nearest cent.)
Let EV----------> <span>expected value </span> we know that
EV = (Probability of Winning)*(Value of Winning) + (Probability of Losing)*(Value of Losing) so EV=0.04*(200)+0.96*(-14)-----> EV=8+(-13.44)-----> EV=-$5.44 So she expects to lose $5.44 every time she plays (this is on average)
