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Gre4nikov [31]
3 years ago
13

What is the domain of g(x) = sqrt x +1

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0
There can be no negative in a sqrt 
so x+1 must be equal or greater then 0
x+1\geq 0
x \geq -1
so all answers must be greater then  or equal to -1
-1,0,1,2,3,4,5,6,7,8
(-1,infinity) is the domain
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Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

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Answer:

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Step-by-step explanation:

You have to find the common denominator in order to get the sum.

multiply 5 to \frac{7}{4} and you get \frac{35}{20}

then to double check the sum, subtract it.

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hope this make sense :/

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