If a = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft, what is the area of the living room and hallway together?
1 answer:
Answer:
The area of the living room and hallway together = 437ft²
Question:
The complete question related to the one above found at 'Geometry in class' is stated below:
Abbey is getting new carpet in her living room and hallway.
The following diagram shows the two together.
If = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft, what is the area of the living room and hallway together?
Find attached the diagram of the question.
Step-by-step explanation:
To determine the area of the living room and hallway together, we would break the diagram into two rectangles.
Calculate the area of each and sum the two outcomes together.
Find attached the diagrams of the solution.
Given: a = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft,
Area of rectangle = length × breadth
Area of rectangle 1 = a × (d-b)
= 38 × (19-15) = 38× 4
Area of rectangle 1 = 152ft²
Area of rectangle 2 = c × b
= 19 × 15 = 285
Area of rectangle 2 = 285ft²
The area of the living room and hallway together = Area of rectangle 1 + Area of rectangle 2
= 152ft² + 285ft²
The area of the living room and hallway together = 437ft²
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Answer:
P-value for this hypothesis test is 0.00175.
Step-by-step explanation:
We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.
A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.
<u><em>Let p = proportion of all living alumni who favored firing the coach</em></u>
SO, Null Hypothesis, : p = 0.50 {means that the majority of alumni are not in favor of firing the coach}
Alternate Hypothesis, : p > 0.50 {means that the majority of alumni are in favor of firing the coach}
The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;
T.S. = ~ N(0,1)
where, = sample proportion of the alumni in the sample who were in favor of firing the coach =
= 0.64
n = sample of alumni = 100
So, <em><u>test statistics</u></em> =
= 2.92
<u>Now, P-value of the hypothesis test is given by ;</u>
P-value = P(Z > 2.92) = 1 - P(Z 2.92)
= 1 - 0.99825 = 0.00175
Therefore, the P-value for this hypothesis test is 0.00175.