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2 years ago

What is that product of 2x + y and 5x -y + 3

Mathematics

2 answers:

poizon [28]2 years ago

7 0

Answer:

10x² + 6x + 3xy + 3y - y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, as shown

(2x + y)(5x - y + 3)

= 2x(5x - y + 3) + y(5x - y + 3) ← distributing

= 10x² - 2xy + 6x + 5xy - y² + 3y ( collect like terms )

= 10x² + 6x + 3xy + 3y - y²

Vlad [161]2 years ago

5 0

The correct answer is:

10 x^2+ 3 xy+ 6 x+ -1 y^2+ 3 y

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Find the GCF 4x^5y^3+8x^4y^4+4x^3y^2

Alekssandra [29.7K]

$4x^5y^3+8x^4y^4+4x^3y^2$

GCF is the greatest common factor

We take GCF of numbers first and then we take GCF for variables

GCF of 4, 8, 4 is 4 because all the numbers are divisible by 4

For variable, lowest exponent is our GCF

GCF of $x^5+x^4+x^3$ is x^3

GCF of $y^3+y^4+y^2$ is y^2

So GCF is 4x^3y^2

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2 years ago

Solve for the unknown in the following diagram. Round the answer to two decimal places.<br>in<br>

Alexxandr [17]

Answer:

172.27 in

Step-by-step explanation:

Apply the Sine Rule

Sine Rule is given as:

$\frac{a}{sin(A)} = \frac{b}{sin(B)} = \frac{c}{sin(C)}$

c = x = ?

C = 180 - (52 + 48) = 80° (sum of triangle)

b = 130 in.

B = 48°

Plug in the values

$\frac{130}{sin(48)} = \frac{x}{sin(80)}$

Multiply both sides by sin(80)

$\frac{130*sin(80)}{sin(48)} = x$

172.274641 = x

x = 172.27 in. (to 2 decimal places)

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2 years ago

How do I solve (fraction) 2/3d=1/6?

IgorLugansk [536]

Answer:

d = 1/4

Step-by-step explanation:

Multiply the equation by the inverse of the coefficient of the variable.

$\dfrac{2}{3}d=\dfrac{1}{6}\\\\\dfrac{3}{2}\cdot\dfrac{2}{3}d=\dfrac{3}{2}\cdot\dfrac{1}{6}\\\\d=\dfrac{3\cdot 1}{2\cdot 6}=\dfrac{3}{12}=\dfrac{3\cdot 1}{3\cdot 4}\\\\d=\dfrac{1}{4}$

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2 years ago

Can you solve for x: (x(5x-2) =0

Alborosie

<h2>please give brainliest plz follow </h2>

7 0

2 years ago

Read 2 more answers

HELP GEOMETRY PLEASE

Alexandra [31]

For each of the problems, twice the angle formed by the chords is equal to half the sum of the angles of the arcs.

So, for the first problem, we have $94 \cdot 2 = x+103$ , so $x = 188 - 103 = 85$ .

For the second, $102 \cdot 2 = x + 118$ , so $x = 204 - 118 = 86$ .

For the last problem, $106 \cdot 2 = x + 88$ , so $x = 212 - 88 = 124$ .

Feel free to comment below if you have any questions!

4 0

2 years ago