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Firlakuza [10]
3 years ago
5

What is the answer to this problem and how do you solve the problem? 2x^-2 y^-3/(3a^-4)

Mathematics
1 answer:
Damm [24]3 years ago
3 0
Well first do you parentheses and the multiply all of your exponets 
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Can someone pls help for brainlest and
zysi [14]

Answer:

so the formula for volume is lent time width times height so 8 times 1 times 2 so the answers is 16

Step-by-step explanation:

7 0
3 years ago
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Find the inverse of the function. <br><br> f(x) = 7x + 2
solmaris [256]
F ( x ) = 7 x + 2
y = 7 x + 2
- 7 x = - y + 2  /*(-1)
7 x = y - 2   / : 7
x = y/7 - 2/7 = ( y - 2 ) / 7
The inverse of the function is:
f^(-1) ( x ) = ( x - 2 ) /7 

3 0
3 years ago
Can you help me find all the seventh roots of unity? what do they look like graphed?
alex41 [277]

Answer:

There are seven seventh roots of unity, e2πki7 , all on the unit circle, r=1 above.

The first one is at θ=2π7=360∘7=5137 ∘ , and there are others at 4π7,6π7,8π7,10π7,12π7 and of course at 0 radians, i.e. unity itself.

How to find?

There are 4 fourth roots of unity and they are 1, i,−1 and−i

Each of the roots of unity can be found by changing the value of k k k in the expression e 2 k π i / n e^{2k\pi i/n} e2kπi/n. By Euler's formula, e 2 π i = cos ⁡ ( 2 π ) + i sin ⁡ ( 2 π ) = 1.

8 0
3 years ago
Help me please !! give me right answer .
harina [27]

Answer:

2.04

Step-by-step explanation:

4 0
3 years ago
Find the general solution of (x+3)y’=2y
gregori [183]

Answer:

y=C(x+3)^2

Step-by-step explanation:

We are given:

\displaystyle (x+3)y^\prime=2y

Separation of Variables:

\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}

So:

\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx

Integrate:

\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx

Integrate:

\displaystyle \ln|y|=2\ln|x+3|+C

Raise both sides to e:

|y|=e^{2\ln|x+3|+C}

Simplify:

|y|=(e^{\ln|x+3|})^2\cdot e^C

So:

|y|=C|x+3|^2

Simplify:

y=\pm C(x+3)^2=C(x+3)^2

5 0
3 years ago
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