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3 years ago

How many moles of carbon are in the sample?

Chemistry

1 answer:

jeka943 years ago

5 0

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3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.

kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

$Percent by mass=\frac{mass of solute}{mass of solution} *100$

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

mass of solute: 3.55 g
mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

$Percentbymass=\frac{3.55}{91.55}*100$

Percent by mass= 3.88%

<u><em>The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%</em></u>

5 0

3 years ago

20 ptsWhich of the labeled structures breaks down food molecules to make ATP? A. the mitochondria B. the Golgi bodies C. the nuc

vaieri [72.5K]

A i think but i could be wrong

3 0

2 years ago

You suspect one of the products of a single replacement is hydrogen gas. How might you experimentally confirm your prediction? C

Nataly_w [17]

The best option i think is b would be my best answer

6 0

3 years ago

How did Wegener explain why fossils of land animals were found on continents that are across oceans from one another?

slamgirl [31]

He explained that with continental drift

8 0

3 years ago

Read 2 more answers

If we have 1.23 mol of NaOH in solution and 0.85 mol of Cl2 gas is available to react, which one is the limiting reactant? Give

Vinil7 [7]

Answer:

NaOH is the limiting reactant.

Explanation:

Hello there!

In this case, since the reaction taking place between sodium hydroxide and chlorine has is:

$NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O$

Which must be balanced according to the law of conservation of mass:

$2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O$

Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:

$n_{NaOH}=0.85molCl_2*\frac{2molNaOH}{1molCl_2}\\\\n_{ NaOH}=1.7molNaOH$

Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.

Regards!

3 0

3 years ago