Hey there!:
HA <=> H⁺ + A⁻
pH = -log[H+] = 6
[ H⁺ ] = 10^-pH
[ H⁺] = 10 ^ -6
[ H⁺ ] = 0.000001 M
Percent dissociation:
[ H⁺ ] / [ HA]o * 100
[ 0.000001 / 0.10 ] * 100
0.00001 * 100 => 0.0010%
Answer D
Hope that helps!
Find the mass of the empirical formula.
You must be given a sample of some kind to calculate the weight or know how many moles are present. Then you figure out what one mol would be. The key step is multiplying the empirical formula numbers by what it takes to make 1 mol.
It would be clearer if we were working from some choices.
it has an electrons in a fixed path together on energy levels.
What best describes the result is a mixture
