All categories

4 years ago

Which of the following should have the largest Henry's law constant (kH) in water?XeCl2COCO2CH3CH3

Chemistry

1 answer:

geniusboy [140]4 years ago

3 0

Answer:

Explanation:

Henry's law constant reflects the solubility of a gas in water. The larger the kH, the more soluble is the gas. There is a rule that states that "like dissolves like", meaning polar is soluble in polar and nonpolar is soluble in nonpolar. Since water is polar, we have to consider the nature of these gases.

Xe nonpolar

Cl₂ nonpolar

CO polar

CO₂ nonpolar

CH₃CH₃ nonpolar

CO is the only polar gas, so it has the largest kH.

You might be interested in

Approximately how many moles of chlorine make up 1.79 × 1023 atoms of chlorine?

e-lub [12.9K]

1.2*10^24# atoms of chlorine

Explanation:
Chlorine gas (#Cl_2#) has two atoms of elemental chlorine in a molecule, so:
#1# mol of #Cl_2# have #6*10^23# molecules of #Cl_2#
#1# molecule of #Cl_2# have #2# atoms per molucule
Then #2*6*10^23 = 1.2*10^24# atoms of chlorine in a mol of chlorine gas

6 0

3 years ago

What is the formula for the ionic compound of strontium and chlorine?

Leno4ka [110]

The formula is SrCl2. hope this helps

8 0

4 years ago

What is the percent by mass of carbon in acetone, c 3 h 6 o?

Tatiana [17]

In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).

Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol

To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C= $( \frac{3(12 g/mol)}{3(12 g/mol)+6(1 g/mol)+16 g/mol} ) x 100%$
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%

5 0

3 years ago

Read 2 more answers

Find the total number of moles of ions produced when 0.347 mol of sodium carbonate dissolves.

Ahat [919]

Answer:

molarity= 0.238 mol L-

Explanation:

The idea here is that you need to use the fact that all the moles of sodium phosphate that you dissolve to make this solution will dissociate to produce sodium cations to calculate the concentration of the sodium cations.

Na 3 PO 4 (aq) → Na + (aq) + PO3−4 (aq)

Use the molar mass of sodium phosphate to calculate the number of moles of salt used to make this solution.

3.25g⋅1 mole N 3PO4 163.9g = 0.01983 moles Na3 PO 4

Now, notice that every

1 mole of sodium phosphate that you dissolve in water dissociates to produce

3bmoles of sodium cations in aqueous solution.

4 0

3 years ago

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen

murzikaleks [220]

Answer: Rate law is, R= 6.02[A]¹[B]²

Explanation in attached image

5 0

3 years ago