Answer: The final temperature of nickel and water is
.
Explanation:
The given data is as follows.
Mass of water, m = 55.0 g,
Initial temp,
,
Final temp,
= ?,
Specific heat of water = 4.184
,
Now, we will calculate the heat energy as follows.
q = 
= 
Also,
mass of Ni, m = 15.0 g,
Initial temperature,
,
Final temperature,
= ?
Specific heat of nickel = 0.444 
Hence, we will calculate the heat energy as follows.
q = 
=
Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

= -(
)
= 
Thus, we can conclude that the final temperature of nickel and water is
.
The pressure in the flask is 3.4 atm.
<em>pV</em> = <em>nRT
</em>
<em>T</em> = (20 + 273.15) K = 293.15 K
<em>p</em> = (<em>nRT</em>)/<em>V</em> = (1.4 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 293.15 K)/10 L = 3.4 atm
Answer:
The answer is Observation.
For you to observe the things around you then you need to use all your sense organs....
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