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LUCKY_DIMON [66]
3 years ago
8

R={(-3, -2), (-3, 0), (-1, 2), (1, 2)} Select all numbers that are in the domain

Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

Domain = -3, -1, 1.

Step-by-step explanation:

Let's find Domains of x-coordinates of the following.

1) (-3, -2) => (x = -3)

2) (-3, 0) => (x = -3)

3) (-1, 2) => (x = -1)

4) (1, 2) => (x = 1)

Hence, value of x = domain .

These x values lie on the x-coordinates .

kirza4 [7]3 years ago
6 0

Answer: D: x = {-3, -1, 1}

<u>Step-by-step explanation:</u>

Domain refers to the x-values of the coordinates.

Coordinates are in the form (x, y) so we are looking for the values on the left side of the parenthesis.

(-3, -2) --> x = -3

(-3, 0)  --> x = -3  <em>already listed above so no need to list it again</em>

(-1, 2)  --> x = -1

(1, 2)  --> x = 1

the x-values are: -3, -1, & 1

so the domain is: x = {-3, -1, 1}

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5.<br> How many tenths are in 2 2/10
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Step-by-step explanation:

In decimal form: 2.2

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Given the similarity statement<br> AJKL ANOP, what's the<br> corresponding side of ON ?
levacccp [35]

Answer:

ON = KJ

Step-by-step explanation:

JKL = NOP

We know the angles match

<J = <N

<K = <O

< L = <P

And we know

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KL =  OP

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Express your answer exactly
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Step-by-step explanation:

6 0
3 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
3 years ago
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